How to calculate Percentage Yield?

Calculate the percentage yield when 31g of methyl salicylate is obtained from 50g of salicylate acid and an equimolar amount of methanol.



C7H6O3 + CH3OH -%26gt; C8H8O3 + H2O



Much appreciated, thanks!How to calculate Percentage Yield?
The percent yield is defined as,



% yield = (actual yield)/(theoretical yield) x 100%



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Right from the start you are given your actual yield, 31 grams of product



Your job is to calculate the theoretical yield via stoichiometry



Step 1 - IS THE EQUATION BALANCED??



Check!



Step 2 -- Molecular weights



salicylic acid, C7H6O3 = 138.12 grams / mole



methyl salicylate, C8H8O3 = 152.15 grams / mole



methanol, CH3OH = 32.04 grams / mole



Step 3 - math



50 grams C7H6O3 x (1 mole / 138.12 grams) x (1 mole C8H8O3 / 1 mole C7H6O3) x (152.15 grams C8H8O3 / 1 mole) = 55.1 g C8H8O3



So theoretically the reaction yields 55.1 grams of product.



Perhaps during the reaction some of the product was spilled in lab....or whatever.

NOTE: Your theoretical value WILL ALWAYS BE LARGER than your actual value



Step 4 -- Plug N Chug



Percent yield = 31/55.1 x 100% = 56% yield