Calculate the percentage abundance of each isotope in naturally occurring Boron?

The relative atomic mass of Boron is 10.8.

Boron exists naturally in two isotopes B-10 and B-11Calculate the percentage abundance of each isotope in naturally occurring Boron?
Let the amount of B-10 be x.



x(10) + (1-x) (11) = 10.8



Solving the equation, you would get 0.2 for B-10, and 0.8 for B-11, giving 20% and 80% respectively.

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