For the reaction represented,calculate the percentage yield of carbo?

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For the reaction represented by the equation CH4 + 2O2 =%26gt; 2H2O + CO2, calculate the percentage yield of carbon dioxide if 1000g of methane react with excess oxygen to produce 2300g of carbon dioxide. (atomic masses: carbon--12.01; hydrogen: 1.01; oxygen--15.99)For the reaction represented,calculate the percentage yield of carbo?
Figure out moles of CH4, then use stoichiometric coefficients to find moles of CO2. Convert to g CO2, then divide actual yield by theoretical and multiply by 100 to get % yield.



mol CH4 = 1000g * 1mol/(12.01 + 4*1.01) g = 62.31 mol CH4



62.31 mol CH4 * 1CO2/1CH4 = 62.31 mol CO2 produced



g CO2 = 62.31 mol * (12.01 + 2*15.99)g/mol = 2742 g CO2 theoretically



% yield = ((actual yield)/(theoretical yield)) * 100





% yield = (2300/2742) * 100 = 83.9% yield CO2