How do i calculate volume percentage?

Suppose a sample of refrigerant gas consisting of a simple mixture of the gases pentafluoroethane (C2HF5) and difluorormethane (CH2F2) has a density of 2.76 g/L with 73.3 amu



Calculate the volume percentage of CH2F2 in the sampleHow do i calculate volume percentage?
First assume an ideal gas... so pv=nrt.

Next, using pv = nrt calc the individual densities of each gas.

n/v = p/rt, covert moles to grams, and you should have the density of each.



Next, (Vol% of component 1)*(density of component 1) + (Vol% of component 2)*(density of component 2) = 2.76



And, (Vol% of component 1) + (Vol% of component 2) = 1



That should work for ya.How do i calculate volume percentage?
This is confusing because the 73.3 amu is too small to be a single molecule of the C2HF5. See below.



C = 12.0107 amu

H = 1.00794 amu

F = 19.9984032 amu



C2HF5 = 2 x 12.0107 + 1.00794 + 5 x 18.9984032 = 120.214 amu



Can you be more specific?