With regards to hazard consequence modeling, you can use pseudo components to equal mixtures of known molecular weights. For a mixture with a MW of 111, there is a certain percentage of 100 and 200 MW pseudo components that equals 111.How do you calculate what percentage of 100 and what percentage of 200 equals the value of 111?
both the previous answers seem to have misinterpreted the question
i take it that the percentages of 100MW %26amp; 200 MW must add up to 100
and the resultant mixture must have a MW of 111
which is a typical mixture problem
let x% of 200MW be used, then (100-x)% of 100MW is used,
to give 100% of a 111MW mixture, so
200x + 100(100-x) = 100*111
2x + 100 - x = 111
x = 11%
ans: 11% of 200MW %26amp; 89% of 100MW
-----How do you calculate what percentage of 100 and what percentage of 200 equals the value of 111?
I believe you are talking about a mixture of the 100 %26amp; 200 that equals 111, if not then ignore this answer.
Are you missing something from this information? You have one equation %26amp; two unknowns.
Let's call % of 100 P1 %26amp; % of 200 P2. So 100*P1 + 200*P2 = 111.
This has infinite solutions. P1=0 %26amp; P2 =55.5% or P1=111% %26amp; P2 = 0 or infinite solutions between these two. The only other thing I think you may mean is that the % of each are equal, so P1 = P2, so we will call it P.
100*P + 200*P = 111 so 300*P = 111 so P = 111/300 so P = 37%How do you calculate what percentage of 100 and what percentage of 200 equals the value of 111?
What percentage of 100 is equal to 111 ?
Answer: 111/100*100 = 111%
What percentage of 200 is equal to 111 ?
Answer: 111/200*100 = 55.5%
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment