What is the percentage of calcium in an ionic compound of unknown composition if a 2.141g sample of the compound is completely dissolved in water and produces 1.222g of CaCO3 upon addition of an excess Na2CO3 solution?
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All I can deduce from here is that CaCO3 is the limiting reagent. Other than that, I don't know how to proceed. Help?
Thanks!How to calculate percentage of calcium in an ionic compound dissolved in water?
Formula weight of CaCO3=40+12+48=100. So Ca is 40/100 by weight of CaCO3. In your sample you had 1.222g of CaCO3 which would have .4*1.222g of Ca in it or .4888g of Ca. That is all you ended with so that is what you started with in a compound that weighed 2.141g
.4888/2.141*100=22.83% Ca in the original sample
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