How to calculate the percentage of acetic acid of vinegar?

i know that the percentage of acetic acid is computed as the volume of soduim hydroxide times its normality equals the number of milligram equivalents of acetic acid neutrilized. The equivalence of acetic acid is 60.0mg or .060g. the 10mL sample of vinegar weights 10.05g. and the volume of sodium hydroxide is 12.54 mL. So how can i calculate the percentage of acetic acid? also i know that vinegar is essentialy a dilute solutin of acetic acid in water, and the law requires that vinegar be at least 4% acetic acid by weight.How to calculate the percentage of acetic acid of vinegar?
Normality of NaOH = ? (needed to calculate the % acetic acid)



assume 0.1 N NaOH



mL NaOH x N of NaOH = milliequivalents of acetic acid



12.54 mL x 0.10 = 1.254 meg of Acetic Acid

1 meq of acetic acid = 0.060 gram



1.254 meq x 0.060 = 0.07524 grams acetic acid

0.07524 gm acetic acid / 10.05 gm vinegar = 0.749%
Can't tell. You need to provide the normality of the hydroxide, which you haven't. Also, most vinegar is labled as to it strength.How to calculate the percentage of acetic acid of vinegar?
You don't give the molarity of NaOH solution. Let's suppose it's N. Let vinegar be called V. Let acetic acid be called HOAc. Molecular weight HOAc = 60.



12.54mLNaOH/10.05gV x NmolNaOH/1000mLNaOH x 1molHOAc/1molNaOH x 60gHOAc/1molHOAc x 100% = %HOAc
No calculation is really required. Just look on the label.How to calculate the percentage of acetic acid of vinegar?
5% mostly